Skip to main content

Shortest Job First Scheduling using HEAP







// Input is from the file "input.txt" in the form (a1,t1),(a2,t2),(a3,t3)  (arrival time, time to complete ie, burst time)




import java.io.*;
import java.util.*;

public class SJFHeap {
    static class point {
        double time;
        double run;
        int no;
        double total;

        point(int i, double a, double b) {
            no = i;
            time = a;
            run = b;
            total = 0;
        }
    }

    static class MHeap {
        private point[] Heap;
        private int maxsize;
        private int size;
        public MHeap(int max) {
            maxsize = max;
            Heap = new point[maxsize];
            size = 0;
        }

        private int leftchild(int pos) {
            return 2 * pos;
        }

        private int rightchild(int pos) {
            return 2 * pos + 1;
        }

        private int parent(int pos) {
            return pos / 2;
        }

        private boolean isleaf(int pos) {
            return ((pos > size / 2) && (pos <= size));
        }

        private void swap(int pos1, int pos2) {
            point tmp;
            tmp = Heap[pos1];
            Heap[pos1] = Heap[pos2];
            Heap[pos2] = tmp;
        }

        public void insert(point elem) {
            size++;
            Heap[size] = elem;
            int current = size;
            int paren = parent(current);
            if (paren >= 1)
                while (Heap[current].run < Heap[paren].run) {
                    swap(current, paren);
                    current = parent(current);
                }
        }

        public void print() {
            int i;
            for (i = 1; i <= size; i++)
                System.out.println("(" + Heap[i].time + "," + Heap[i].run + ")");
        }

        public point removemin() {
            swap(1, size);
            size--;
            if (size != 0)
                pushdown(1);

            return Heap[size + 1];
        }

        private void pushdown(int position) {
            int smallestchild;
            while (!isleaf(position)) {
                smallestchild = leftchild(position);
                if ((smallestchild < size)
                        && (Heap[smallestchild].run > Heap[smallestchild + 1].run))
                    smallestchild = smallestchild + 1;
                if (Heap[position].run <= Heap[smallestchild].run)
                    return;
                swap(position, smallestchild);
                position = smallestchild;
            }
        }
    }

    public static void main(String[] args) throws IOException {
        MHeap h = new MHeap(10);
        FileInputStream fstream = new FileInputStream("input.txt");
        DataInputStream in = new DataInputStream(fstream);
        BufferedReader br = new BufferedReader(new InputStreamReader(in));
        point ele;
        String strLin;
        strLin = in.readLine();
        StringTokenizer st = new StringTokenizer(strLin, " (,)");
        int mp = st.countTokens();
        point[] task = new point[mp / 2];
        point[] tem = new point[mp / 2];
        int l = 0, num;
        while (st.hasMoreTokens())
        {
            String x = st.nextToken();
            double x1 = Double.parseDouble(x);
            String y = st.nextToken();
            double y1 = Double.parseDouble(y);
            point pt = new point(l + 1, x1, y1);
            task[l] = pt;
            l++;
        }
        num = l;
        int j = 0, i = 0, killed = 0;
        double now = 0, prev = 0, diff, kill = 0;
        point pt = task[0];
        while (i != num)
        {
            now = task[i].time;
            if (i == 0)
            {
                h.insert(task[i]);
                i++;
                prev = now;
            }
            else
            {
                pt = h.removemin();
                diff = now - prev;
                if (pt.run > diff)
                {
                    pt.run = pt.run - diff;
                    h.insert(pt);
                }
                else
                {
                    pt.total = prev + pt.run - pt.time;
                    kill = prev + pt.run;
                    pt.run = 0;
                    tem[j++] = pt;
                }
                h.insert(task[i]);
                prev = kill > 0 ? kill : now;
                i++;
            }
        }

        h.insert(h.removemin());
        while (h.size != 0)
        {
            pt = h.removemin();
            pt.total = prev + pt.run - pt.time;
            tem[j++] = pt;
            prev = prev + pt.run;
        }
        for (i = 0; i < j; i++)
            System.out.println("Process-" + tem[i].no + " processed for " + tem[i].total);
    }
}

Comments

Popular posts from this blog

JavaScript - Singleton Pattern

The singleton design pattern is probably the simplest and most common pattern in JavaScript. So why should you use the singleton pattern? Encapsulation of members & functions Creates its own Namespace A singleton is a single instance object Encourages code reuse Improves readability because you can logically organise your code The point of a singleton is to only have one instance. A shopping cart is a good example of something that you may want only a single instance of at one time. The simplest form of Singleton is an object literal. This loose form of Singleton cannot be instantiated. All of the members are now accessible through the Singleton variable, accessible through dot notation. var myCart = {     self: this ,     totalCost: 0,     totalQty: 0,     cart: {},     getCart: function (){ },     updateCart: function (){ } }; alert( "Total cost: ...

Setting JVM Heap size at runtime

To set the JVM heap size, compile the program normally. For example, consider Runtime.java program. Compilation: javac Runtime.java Now, to set minimum heap size(let, 16 MB) required by JVM, run the program as follows : java -Xms16m Runtime  We can also restrict maximum size(let 512 MB) utilized by JVM: java -Xmx512m Runtime  Both these options can also be combined to specify upper and lower bounds of JVM heap size: java -Xms16m -Xmx512m Runtime Now you can run a program that requires huge computational space.

Reverse Engineering : Extract contents from .img file

Unyaffs is a program to extract files from a YAFFS2 file system image. Currently it can only extract images created by mkyaffs2image. Download the source from here . Compiling : Extract the contents into a suitable place and run the following command make Usage : unyaffs [options] <image_file_name> [<extract_directory>] Options: -d detection of flash layout, no extraction -b spare contains bad block information -c <chunk size> set chunk size in KByte (default: autodetect, max: 16) -s <spare size> set spare size in Byte (default: autodetect, max: 512) -t list image contents -v verbose output -V print version Source: Official github repository